(x+3)^2-5=-30

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Solution for (x+3)^2-5=-30 equation: 



(x+3)^2-5=-30

We move all terms to the left:

(x+3)^2-5-(-30)=0

We add all the numbers together, and all the variables

(x+3)^2+25=0

We move all terms containing x to the left, all other terms to the right

(x+3)^2=-25

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